2.25x^2-4=0

Solution for 2.25x^2-4=0 equation:

2.25x^2-4=0

a = 2.25; b = 0; c = -4;
Δ = b2-4ac
Δ = 02-4·2.25·(-4)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6}{2*2.25}=\frac{-6}{4.5}
=-1+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6}{2*2.25}=\frac{6}{4.5}
=1+1/3
$